JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    The decomposition of \[{{N}_{2}}{{O}_{5}}\] is a first order reaction represented by \[{{N}_{2}}{{O}_{5}}\to {{N}_{2}}{{O}_{4}}+\frac{1}{2}{{O}_{2}}\]. After 15 minutes the volume of \[{{O}_{2}}\] produced is \[9\,ml\] and at the end of the reaction \[35\,ml\]. The rate constant is equal to [MP PET 1995]

    A)   \[\frac{1}{15}\,\ln \,\frac{35}{44}\]       

    B)   \[\frac{1}{15}\,\ln \,\frac{44}{26}\]

    C)   \[\frac{1}{15}\,\ln \,\frac{44}{35}\]       

    D)   \[\frac{1}{15}\,\ln \,\frac{35}{26}\]

    Correct Answer: D

    Solution :

                    \[K=\frac{1}{t}\log e\left( \frac{a}{a-x} \right)=\frac{1}{15}\log e\left( \frac{35}{35-9} \right)\] \[=\frac{1}{15}\log e\left( \frac{35}{26} \right)\]


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