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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    \[A+2B\to C+D\]. If \[-\frac{d[A]}{dt}=5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]1, then \[-\frac{d[B]}{dt}\] is                   [DPMT  2005]

    A)                 \[2.5\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]               

    B)                 \[5.0\times {{10}^{-4}}mol\,{{l}^{-1}}{{s}^{-1}}\]

    C)                 \[2.5\times 10-3mol\,{{l}^{-1}}{{s}^{-1}}\]           

    D)                 \[1.0\times {{10}^{-3}}mol\,{{l}^{-1}}{{s}^{-1}}\]

    Correct Answer: A

    Solution :

               \[A+2B\to C+D\]                    \[\frac{-d[A]}{dt}=5\times {{10}^{-4}}\]                                 \[-\frac{1}{2}\frac{d[B]}{dt}=\frac{5\times {{10}^{-4}}}{2}=2.5\times {{10}^{-4}}mo{{l}^{-1}}{{\sec }^{-1}}\]


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