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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    For the reaction \[2{{N}_{2}}{{O}_{5}}\to 4N{{O}_{2}}+{{O}_{2}}\]rate of reaction and rate constant are \[1.02\times {{10}^{-4}}\]and \[3.4\times {{10}^{-5}}{{\sec }^{-1}}\] respectively. The concentration of \[{{N}_{2}}{{O}_{5}}\] at that time will be [BHU 2001]

    A)                 \[1.732\]             

    B)                 3

    C)                 \[1.02\times {{10}^{-4}}\]            

    D)                 \[3.4\times {{10}^{5}}\]

    Correct Answer: B

    Solution :

               \[R=K[A]\], \[1.02\times {{10}^{-4}}=3.4\times {{10}^{-5}},\,[{{N}_{2}}{{O}_{5}}]\]                                 or \[({{N}_{2}}{{O}_{5}})\]\[=\frac{1.02\times {{10}^{-4}}}{3.4\times {{10}^{-5}}},\,K=3\]


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