JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    The reaction                 \[{{N}_{2}}{{O}_{5}}\,(\text{in}\,CC{{l}_{4}}\,\text{solution})\to 2N{{O}_{2}}(\text{solution})+\frac{1}{2}{{O}_{2}}(g)\] is of first order in \[{{N}_{2}}{{O}_{5}}\]  with rate constant \[6.2\times {{10}^{-1}}{{s}^{-1}}.\] What is the value of rate of reaction when \[[{{N}_{2}}{{O}_{5}}]=1.25\,mole\,{{l}^{-1}}\]               [AFMC 1998]

    A)                 \[7.75\times {{10}^{-1}}mole\,{{l}^{-1}}{{s}^{-1}}\]         

    B)                 \[6.35\times {{10}^{-3}}mole\,{{l}^{-1}}{{s}^{-1}}\]

    C)                 \[5.15\times {{10}^{-5}}mole\,{{l}^{-1}}{{s}^{-1}}\]          

    D)                 \[3.85\times {{10}^{-1}}mole\,{{l}^{-1}}\,{{s}^{-1}}\]

    Correct Answer: A

    Solution :

               Rate \[=K({{N}_{2}}{{O}_{5}})=6.2\times {{10}^{-1}}\times 1.25\]                                 \[=7.75\times {{10}^{-1}}\,\,mol\,\,{{l}^{-1}}\,\,{{s}^{-1}}\]


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