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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    \[{{t}_{\frac{1}{4}}}\] can be taken as the time taken for the concentration of a reactant to drop to \[\frac{3}{4}\] of its initial value. If the rate constant for a first order reaction is \[K\], the \[{{t}_{\frac{1}{4}}}\] can be written as [AIEEE 2005]

    A)                 \[0.10/K\]           

    B)                 \[0.29/K\]

    C)                 \[0.69/K\]           

    D)                 \[0.75/K\]

    Correct Answer: B

    Solution :

                    \[{{t}_{1/4}}=\frac{2.303}{K}\log \frac{1}{1-\frac{1}{4}}=\frac{0.29}{K}\].


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