A) Saponification of\[C{{H}_{3}}COO{{C}_{2}}{{H}_{5}}\]? Second order reaction
B) Hydrolysis of \[C{{H}_{3}}COOC{{H}_{3}}\]? Pseudo uni-molecular reaction
C) Decomposition of \[{{H}_{2}}{{O}_{2}}\] ? First order reaction
D) Combination of \[{{H}_{2}}\]and \[B{{r}_{2}}\] to give \[HBr\] ? Zero order reaction
Correct Answer: D
Solution :
\[{{H}_{2}}+B{{r}_{2}}\] ⇌ \[2HBr\] is a 1.5 order reaction i.e., \[K=[{{H}_{2}}]{{[B{{r}_{2}}]}^{1/2}}\].
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