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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    The reaction \[A\to B\]follows first order kinetics. The time taken for 0.8 mole of A to produce 0.6 mole of B is 1 hour. What is the time taken for conversion of 0.9 mole of A to produce 0.675 mole of B           [CBSE PMT 2003]

    A)                 2 hours

    B)                 1 hour

    C)                 0.5 hour              

    D)                 0.25 hour

    Correct Answer: B

    Solution :

               \[k=\frac{2.303}{t}\log \frac{0.8}{0.6}=2.303\log \frac{4}{3}\]                                 \[t=\frac{2.303}{k}\log \frac{0.9}{0.675}=\frac{2.303}{k}\log \frac{4}{3}\]; \[t=1\]hour.


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