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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    75% of a first order reaction was completed in 32 minutes when was 50% of the reaction completed [AMU 1999; Kerala (Med.) 2003]

    A)                 16 min.

    B)                 24 min.

    C)                 8 min.   

    D)                 4 min.

    Correct Answer: A

    Solution :

               \[k=\frac{2.303}{t}\log \left( \frac{a}{a-x} \right)\]                    \[k=\frac{2.303}{32}\log \left( \frac{100}{100-75} \right)\]     .? (i)            \[k=\frac{2.303}{t}\log \left( \frac{100}{100-50} \right)\]     ?.(ii)                                 from the  two equation (i) and (ii), \[t=16\]minutes.


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