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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    For a first order reaction velocity constant, \[K={{10}^{-3}}{{s}^{-1}}\]. Two third life for it would be         [MP PET 2001; UPSEAT 2003]

    A)                 1100 s   

    B)                 2200 s

    C)                 3300 s   

    D)                 4400 s

    Correct Answer: C

    Solution :

               We know that  \[k=\frac{2.303}{t}\log \frac{a}{a-x}\]  \[{{10}^{-3}}=\frac{2.303}{t}\log \frac{a}{(a-\frac{2a}{3})},\,\,{{10}^{-3}}=\frac{2.303}{t}\log \,3\]                                 \[{{10}^{-3}}=\frac{2.303}{t}\times 0.4771,\,\,t=\frac{2.303\times 0.4771}{{{10}^{-3}}}\]                \[=3300\,\,\sec \]


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