A) \[1.29\times {{10}^{-2}}{{\min }^{-1}}\]
B) \[2.29\times {{10}^{-2}}{{\min }^{-1}}\]
C) \[3.29\times {{10}^{-2}}{{\min }^{-1}}\]
D) \[4.40\times {{10}^{-2}}{{\min }^{-1}}\]
Correct Answer: A
Solution :
Given A = 2.00 m, t = 200 min and a(a-x) = 0.15 m we know \[k=\frac{2.303}{t}\log \frac{a}{a-x}=\frac{2.303}{200}\log \frac{2.00}{0.15}\] \[=\frac{2.303}{200}\times (0.301+0.824)=1.29\times {{10}^{-2}}{{\min }^{-1}}\]
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