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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    75% of a first order reaction is completed in 30 minutes. What is the time required for 93.75% of the reaction (in minutes)                                              [KCET 2001]

    A)                 45          

    B)                 120

    C)                 90          

    D)                 60

    Correct Answer: D

    Solution :

               \[k=\frac{2.303}{t}\log \left( \frac{a}{a-x} \right)\]; \[k=\frac{2.303}{30}\log \left( \frac{100}{100-75} \right)\]                                 \[k=\frac{2.303}{t}\log \left( \frac{100}{100-93.75} \right)\]  Put the value of \[K\] from above equation we get the value of \[t\] therefore  \[\therefore \ \ \ t=60\,\min .\]


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