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JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    The rate for a first order reaction is \[0.6932\times {{10}^{-2}}mol\,{{l}^{-1}}mi{{n}^{-1}}\] and the initial concentration of the reactants is 1M, \[{{T}_{1/2}}\] is equal to               [JIPMER (Med.) 2001]

    A)                 \[6.932\] min    

    B)                 100 min

    C)                 \[0.6932\times {{10}^{-3}}\] min              

    D)                 \[0.6932\times {{10}^{-2}}\] min

    Correct Answer: B

    Solution :

                    \[r=k{{[\text{reactant}]}^{-1}}\]\[\therefore k=\frac{0.693\times {{10}^{-2}}}{1}\]also \[{{t}_{1/2}}=\frac{0.693}{k}=\frac{0.693}{0.693\times {{10}^{-2}}}=100\,\min \].


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