JEE Main & Advanced Chemistry Chemical Kinetics / रासायनिक बलगतिकी Question Bank Rate law and Rate Constant

  • question_answer
    For a reactions \[A+B\to \]product, it was found that rate of reaction increases four times if concentration of ?A? is doubled, but the rate of reaction remains unaffected. If concentration of ?B? is doubled. Hence, the rate law for the reaction is           [MP PET/PMT 1998; MP PMT 2003]

    A)                 \[\text{rate}=k[A][B]\]

    B)                 \[\text{rate}=k{{[A]}^{2}}\]

    C)                 \[\text{rate}=k{{[A]}^{2}}{{[B]}^{1}}\]  

    D)                 \[\text{rate}=k{{[A]}^{2}}{{[B]}^{2}}\]

    Correct Answer: B

    Solution :

               Let the rate of reaction depends on xth power of [A]. Then                    \[{{r}_{1}}=k{{[A]}^{x}}\] and \[{{r}_{2}}=k{{[2A]}^{x}}\]                    \[\therefore \frac{{{r}_{1}}}{{{r}_{2}}}=\frac{{{[A]}^{x}}}{{{[2A]}^{x}}}=\frac{1}{4}={{\left( \frac{1}{2} \right)}^{2}}\]    \[(\because {{r}_{2}}=4{{r}_{1}})\] \[\therefore x=2\]. As the reaction rate does not depend upon the concentration of B. Hence, the correct rate law will be \[\text{rate}=K{{[A]}^{2}}{{[B]}^{o}}\] or  \[=K{{[A]}^{2}}\]


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