A) 1/9
B) 1/27
C) 1/6
D) 1/8
Correct Answer: D
Solution :
By using \[A={{A}_{0}}{{\left( \frac{1}{2} \right)}^{\frac{t}{{{T}_{1/2}}}}}\] Þ \[\frac{A}{{{A}_{0}}}={{\left( \frac{1}{2} \right)}^{9/3}}=\frac{1}{8}\]
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