A) \[4.6\times {{10}^{12}}atoms/s\]
B) \[2.3\times {{10}^{11}}atoms/s\]
C) \[4.6\times {{10}^{10}}atoms/s\]
D) \[2.3\times {{10}^{8}}\]
Correct Answer: D
Solution :
\[\frac{dN}{dt}=-\lambda N\Rightarrow \left| \frac{dN}{dt} \right|=\frac{0.693}{{{T}_{1/2}}}\times N\] \[=\frac{0.693}{1.2\times {{10}^{7}}}\times 4\times {{10}^{15}}=2.3\times {{10}^{8}}atoms/\sec \]
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