A) \[{{\left( \frac{287}{7} \right)}^{4}}\]
B) 16
C) 4
D) 2
Correct Answer: B
Solution :
For a block body rate of energy \[\frac{Q}{t}=P=A\sigma {{T}^{4}}\] Þ \[P\propto {{T}^{4}}\] Þ \[\frac{{{P}_{1}}}{{{P}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}={{\left\{ \frac{(273+7)}{(273+287)} \right\}}^{4}}=\frac{1}{16}\]
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