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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    Energy is being emitted from the surface of a black body at \[{{127}^{o}}C\] temperature at the rate of \[1.0\times {{10}^{6}}J/\sec -{{m}^{2}}\]. Temperature of the black body at which the rate of energy emission is \[16.0\times {{10}^{6}}J/\sec -{{m}^{2}}\] will be [MP PMT 1991; AFMC 1998]

    A)            \[{{254}^{o}}C\]                  

    B)            \[{{508}^{o}}C\]

    C)            \[{{527}^{o}}C\]                  

    D)            \[{{727}^{o}}C\]

    Correct Answer: C

    Solution :

               \[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\]Þ\[{{T}_{2}}={{\left( \frac{{{E}_{2}}}{{{E}_{1}}} \right)}^{1/4}}\times {{T}_{1}}={{(16)}^{1/4}}\times (273+127)\]            Þ T2 \[=800\ K={{527}^{o}}C\]                                        


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