A) \[{{200}^{o}}C\]
B) \[200\ K\]
C) \[{{800}^{o}}C\]
D) 800 K
Correct Answer: D
Solution :
\[\frac{{{E}_{2}}}{{{E}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\]Þ \[\frac{2}{1}={{\left( \frac{420+273}{T} \right)}^{4}}\]\[={{\left( \frac{673}{T} \right)}^{4}}\] Þ \[T={{2}^{1/4}}\times 673\] = 800K.
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