A) 46%
B) 40%
C) 30%
D) 80%
Correct Answer: A
Solution :
\[Q\propto {{T}^{4}}\] Þ \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\] If \[{{T}_{1}}=T\] then \[{{T}_{2}}=T+\frac{10}{100}T=1.1T\] Þ \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{T}{1.1T} \right)}^{4}}\] Þ \[{{Q}_{2}}=1.46\,{{Q}_{1}}\] Þ % increase in energy \[=\frac{{{Q}_{2}}-{{Q}_{1}}}{{{Q}_{1}}}\times 100=46%\]
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