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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    A black body at a temperature of 127°C  radiates heat at the rate of 1 cal/cm2 ´ sec. At a temperature of 527°C the rate of heat radiation from the body in (cal/cm2 ´ sec) will be  [MP PET 2002]

    A)            16.0                                          

    B)            10.45

    C)            4.0 

    D)            2.0

    Correct Answer: A

    Solution :

               \[\frac{{{Q}_{2}}}{{{Q}_{1}}}=\frac{T_{2}^{4}}{T_{1}^{4}}={{\left( \frac{273+527}{273+127} \right)}^{4}}={{\left( \frac{800}{400} \right)}^{4}}\]Þ\[{{Q}_{2}}=16\frac{cal}{c{{m}^{2}}\times s}\]


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