A) \[16\ E\]
B) \[{{T}_{2}}=8{{T}_{1}}\]
C) \[4\ E\]
D) \[E\]
Correct Answer: A
Solution :
\[\frac{{{E}_{1}}}{{{E}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}\Rightarrow \frac{E}{{{E}_{2}}}={{\left( \frac{273+0}{273+273} \right)}^{4}}\]\[\Rightarrow {{E}_{2}}=16\ E\].
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