2. Questions Bank
  3. JEE Main & Advanced
  4. Physics
  5. Transmission of Heat

JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    The original temperature of a black body is \[{{727}^{o}}C.\]The temperature at which this black body must be raised so as to double the total radiant energy, is    [Pb. PMT 2001]

    A)            971 K                                       

    B)            1190 K

    C)            2001 K                                     

    D)            1458 K

    Correct Answer: B

    Solution :

                       \[\frac{{{Q}_{2}}}{{{Q}_{1}}}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\Rightarrow \frac{2}{1}={{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\] \[\Rightarrow T_{2}^{4}=2\times T_{1}^{4}=2\times {{(273+727)}^{4}}\]Þ \[{{T}_{2}}=1190K\].


You need to login to perform this action.
You will be redirected in 3 sec spinner