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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    The ratio of energy of emitted radiation of a black body at \[{{27}^{o}}C\] and \[{{927}^{o}}C\] is              [Pb. PMT 1995; CPMT 1997, 2000; CBSE PMT 2000; DPMT 1998, 02, 03]

    A)            1 : 4                                          

    B)            1 : 16

    C)            1 : 64                                        

    D)            1 : 256

    Correct Answer: D

    Solution :

               \[\frac{{{Q}_{1}}}{{{Q}_{2}}}={{\left( \frac{{{T}_{1}}}{{{T}_{2}}} \right)}^{4}}={{\left( \frac{273+27}{273+927} \right)}^{4}}={{\left( \frac{1}{4} \right)}^{4}}=\frac{1}{256}\]


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