JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Stefan's law

  • question_answer
    The energy emitted per second by a black body at \[{{27}^{o}}C\] is \[10\ J\]. If the temperature of the black body is increased to \[{{327}^{o}}C\], the energy emitted per second will be [CPMT 1999; DCE 1999]

    A)            \[20\ J\]                                 

    B)            \[40\ J\]

    C)            \[80\ J\]                                 

    D)            \[160\ J\]

    Correct Answer: D

    Solution :

                       \[{{(Q)}_{Black\,body}}=A\sigma {{T}^{4}}t\] Þ \[Q\propto {{T}^{4}}\] Þ \[{{Q}_{2}}={{Q}_{1}}{{\left( \frac{{{T}_{2}}}{{{T}_{1}}} \right)}^{4}}\]\[=10\,{{\left( \frac{273+327}{273+27} \right)}^{4}}\]\[=10\,{{\left( \frac{600}{300} \right)}^{4}}=160J\]


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