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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Newton's Law of Cooling

  • question_answer
    The temperature of a body falls from 62oC to 50oC in 10 minutes. If the temperature of the surroundings is 26oC, the temperature in next 10 minutes will become    [RPMT 2002]

    A)            42oC                                         

    B)            40oC

    C)            56oC                                         

    D)            55oC

    Correct Answer: A

    Solution :

                       \[\frac{62-50}{10}=K\left( \frac{62+50}{2}-26 \right)\]Þ \[\frac{6}{5}=K\times 30\] Þ \[K=\frac{1}{25}\]            And, \[\frac{50-\theta }{10}=\frac{1}{25}\left( \frac{50+\theta }{2}-26 \right)\] Þ \[\theta =42{}^\circ \]C.


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