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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Newton's Law of Cooling

  • question_answer
    A liquid cools from 50 o C to 45 o C in 5 minutes and from  45 o C to 41.5 o C in the next 5 minutes. The temperature of the surrounding is                                                                 [BCECE 2004]

    A)            27 o C                                       

    B)            40.3 o C

    C)            23.3 o C                                    

    D)            33.3 o C

    Correct Answer: D

    Solution :

                       \[\frac{50-45}{5}=K\left( \frac{50+45}{2}-{{\theta }_{0}} \right)\]                            ?..(i)                    \[\frac{45-41.5}{5}=K\left( \frac{45+41.5}{2}-{{\theta }_{0}} \right)\]    ?..(ii)            Solving equation (i) and (ii) we set \[{{\theta }_{0}}=33.3\ {}^\circ C\].


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