A) \[{{R}_{1}}:{{R}_{2}}=3:2\]
B) \[{{R}_{1}}:{{R}_{2}}=5:4\]
C) \[{{R}_{1}}:{{R}_{2}}=2:3\]
D) \[{{R}_{1}}:{{R}_{2}}=4:5\]
Correct Answer: A
Solution :
Initially at t = 0 Rate of cooling (R) µ Fall in temperature of body (q ? q0) Þ \[\frac{{{R}_{1}}}{{{R}_{2}}}=\frac{{{\theta }_{1}}-{{\theta }_{0}}}{{{\theta }_{2}}-{{\theta }_{0}}}=\frac{100-40}{80-40}=\frac{3}{2}\]
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