JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Newton's Law of Cooling

  • question_answer
    It takes 10 minutes to cool a liquid from 61oC to 59oC. If room temperature is 30oC then time taken in cooling from 51oC to 49oC is                                                                             [RPET 2003]

    A)            10 min                                     

    B)            11 min

    C)            13 min                                     

    D)            15 min

    Correct Answer: D

    Solution :

                       In first case \[\frac{61-59}{10}=K\left[ \frac{61+59}{2}-30 \right]\]          ?.(i)                    In second case \[\frac{51-49}{10}=K\left[ \frac{51+49}{2}-30 \right]\]   ?.(ii)            By solving \[t=15\]min.


You need to login to perform this action.
You will be redirected in 3 sec spinner