A) \[{{36.6}^{o}}C\]
B) \[{{33.3}^{o}}C\]
C) \[{{35}^{o}}C\]
D) \[{{30}^{o}}C\]
Correct Answer: D
Solution :
In first case \[\frac{50-40}{10}=K\left[ \frac{50+40}{2}-20 \right]\] ?.(i) In second case \[\frac{40-{{\theta }_{2}}}{10}=K\left[ \frac{40+{{\theta }_{2}}}{2}-20 \right]\] ?.(ii) By solving \[{{\theta }_{2}}={{33.3}^{o}}C\].
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