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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Newton's Law of Cooling

  • question_answer
    A body takes 5 minutes for cooling from \[{{50}^{o}}C\] to \[{{40}^{o}}C.\] Its temperature comes down to \[{{33.33}^{o}}C\] in next 5 minutes. Temperature of surroundings is                      [MP PMT 2002]

    A)            \[{{15}^{o}}C\]                    

    B)            \[{{20}^{o}}C\][L1]

    C)            \[{{25}^{o}}C\]                    

    D)            \[{{10}^{o}}C\]

    Correct Answer: B

    Solution :

                       In first case \[\frac{50-40}{5}=K\left[ \frac{50+40}{2}-{{\theta }_{0}} \right]\]    ?.(i)                    In second case \[\frac{40-33.33}{5}=K\left[ \frac{40+33.33}{2}-\theta  \right]\]                ?.(ii)            By solving \[{{\theta }_{0}}={{20}^{o}}C\].


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