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JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Newton's Law of Cooling

  • question_answer
    In a room where the temperature is \[{{30}^{o}}C\], a body cools from \[{{61}^{o}}C\] to \[{{59}^{o}}C\] in 4 minutes. The time (in min.) taken by the body to cool from \[{{51}^{0}}C\]to \[{{49}^{0}}C\] will be [UPSEAT 2000]

    A)            4 min                                       

    B)            6 min

    C)            5 min                                       

    D)            8 min

    Correct Answer: B

    Solution :

                       First case, \[\frac{61-59}{4}=K\left[ \frac{61+59}{2}-30 \right]\]               ?..(i) Second case, \[\frac{51-49}{t}=K\left[ \frac{51+49}{2}-30 \right]\]            ?..(ii) By solving equation (i) and (ii) we get  t = 6 min.


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