JEE Main & Advanced Physics Transmission of Heat Question Bank Radiation Newton's Law of Cooling

  • question_answer
    A body cools from \[{{60}^{o}}C\] to \[{{50}^{o}}C\] in 10 minutes. If the room temperature is \[{{25}^{o}}C\] and assuming Newton's law of cooling to hold good, the temperature of the body at the end of the next  10 minutes will be [MP PMT/PET 1998; BHU 2000; Pb. PMT 2001]

    A)            \[{{38.5}^{o}}C\]                

    B)            \[{{40}^{o}}C\]

    C)            \[{{42.85}^{o}}C\]              

    D)            \[{{45}^{o}}C\]

    Correct Answer: C

    Solution :

                       \[\frac{60-50}{10}=K\left( \frac{60+50}{2}-25 \right)\]                    ?..(i)                    \[\frac{50-\theta }{10}=K\left[ \frac{50+\theta }{2}-25 \right]\]                               ?..(ii)            On dividing, we get \[\frac{10}{50-\theta }=\frac{60}{\theta }\Rightarrow \theta ={{42.85}^{o}}C\]


You need to login to perform this action.
You will be redirected in 3 sec spinner