A) \[{{30}^{o}}C\]
B) \[{{36}^{o}}C\]
C) \[{{26}^{o}}C\]
D) \[{{20}^{o}}C\]
Correct Answer: C
Solution :
\[\frac{{{\theta }_{1}}-{{\theta }_{2}}}{t}=K\left[ \frac{{{\theta }_{1}}+{{\theta }_{2}}}{2}-{{\theta }_{0}} \right]\] In the first 10 minute \[\frac{62-50}{10}=K\,\left[ \frac{62+50}{2}-{{\theta }_{0}} \right]\]Þ \[1.2=\,K\,[56-{{\theta }_{0}}]\] .... (i) \[\frac{50-42}{10}=K\,\left[ \frac{50+42}{2}-{{\theta }_{0}} \right]\]Þ \[0.8=\,K\,[46-{{\theta }_{0}}]\] .... (ii) from equations (i) and (ii)\[\frac{1.2}{0.8}=\frac{(56-{{\theta }_{0}})}{(46-{{\theta }_{0}})}\] Þ \[{{\theta }_{0}}=26{}^\circ C\]
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