A) \[{{e}_{\lambda }}={{a}_{\lambda }}={{E}_{\lambda }}\]
B) \[{{e}_{\lambda }}{{E}_{\lambda }}={{a}_{\lambda }}\]
C) \[{{e}_{\lambda }}={{a}_{\lambda }}{{E}_{\lambda }}\]
D) \[{{e}_{\lambda }}{{a}_{\lambda }}{{E}_{\lambda }}\]= constant
Correct Answer: C
Solution :
According to Kirchoff?s law, the ratio of emissive power to absorptive power is same for all bodies is equal to the emissive power of a perfectly black body i.e., \[{{\left( \frac{e}{a} \right)}_{body}}={{E}_{\text{Black}\,\text{body}}}\] for a particular wave length \[{{\left( \frac{{{e}_{\lambda }}}{{{a}_{\lambda }}} \right)}_{\text{body}}}={{({{E}_{\lambda }})}_{\text{Black}\,\text{body}}}\] Þ \[{{e}_{\lambda }}={{a}_{\lambda }}{{E}_{\lambda }}\]
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