question_answer

A walks 10 metres in front and 10 metres to the right. Then every time turning to his left, he walks 5, 15 and 15 metres respectively. How far is he now from his starting point?

A) 5 metres

B) 10 metres

C) 15 metres

D) 20 metres

E) None of these

Correct Answer: A

Solution :

Explanation Option (a) is correct. The movements of A are as shown in figure (0 to P, P to Q, Q. to R, R to S and S co T) Since TS = OP + QR, so T lies in line with O \[\therefore \] A's distance from the starting point O = OT = (RS - PQ) = (15 - 10) m = 5m