A) 10 metres North
B) 20 meter South
C) 20 metres North
D) 10 metres South
Correct Answer: B
Solution :
Explanation: The movements of Sanjeev from A to F are shown in figure.
Clearly, Sanjeev?s distance from stating point \[A=AF=\left( AB+BF \right)\] \[=\text{ }AB+\left( BE-EF \right)=AB+\left( CD-EF \right)\] \[=\left[ 10+\left( 20-10 \right) \right]\text{ }m=\left( 10+10 \right)m=20\text{ }m\] Also, F lies to the South of A. So, Sanjeev is 20 metres to the south of his starting point.
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