JEE Main & Advanced Chemistry Structure of Atom Question Bank Quantum number, Electronic configuration and Shape of orbitals

  • question_answer Correct set of four quantum numbers for valence electron of rubidium (Z = 37) is [IIT 1984; JIPMER 1999; UPSEAT  2003]

    A)                 \[5,\,0,\,0,\,+\frac{1}{2}\]           

    B)                 \[5,\,1,\,0,\,+\frac{1}{2}\]

    C)                 \[5,\,1,\,1,\,+\frac{1}{2}\]           

    D)                 \[6,\,0,\,0,\,+\,\frac{1}{2}\]

    Correct Answer: A

    Solution :

               Electronic configuration of \[R{{b}_{(37)}}\] is                    \[1{{s}^{2}}2{{s}^{2}}2{{p}^{6}}3{{s}^{2}}3{{p}^{6}}3{{d}^{10}}4{{s}^{2}}4{{p}^{6}}5{{s}^{1}}\]            So for the valence shell electron \[(5{{s}^{1}})\]                 \[n=5,\,l=0,\,m=0,\,s=+\frac{1}{2}\]

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