A) 1
B) 3
C) 4
D) 9
Correct Answer: D
Solution :
When \[n=3\] shell, the orbitals are \[{{n}^{2}}={{3}^{2}}=9\] . No. of electrons \[=2{{n}^{2}}\] Hence no. of orbital \[=\frac{2{{n}^{2}}}{2}={{n}^{2}}\].You need to login to perform this action.
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