JEE Main & Advanced Chemistry Structure of Atom Question Bank Quantum number, Electronic configuration and Shape of orbitals

  • question_answer The four quantum numbers of the outermost orbital of \[K\]  (atomic no. =19) are           [MP PET 1993, 94]

    A)                 \[n=2,\,l=0,\,m=0,\,s=+\frac{1}{2}\]

    B)                 \[n=4,\,l=0,\,m=0,\,s=+\frac{1}{2}\]

    C)                 \[n=3,\,l=1,\,m=1,\,s=+\frac{1}{2}\]

    D)                 \[n=4,\,l=2,\,m=-1,\,s=+\frac{1}{2}\]

    Correct Answer: B

    Solution :

               \[{{K}_{19}}=1{{s}^{2}},\,2{{s}^{2}}\,2{{p}^{6}},\,3{{s}^{2}}\,3{{p}^{6}},\,4{{s}^{1}}\]                    for \[4{{s}^{1}}\]electrons.                 \[n=4,\,l=0,\,m=0\] and \[s=+\frac{1}{2}.\]


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