A) Five
B) Eighteen
C) Seventeen
D) Thirty five
Correct Answer: C
Solution :
The atomic number of bromine is 35 and the electronic configuration of \[Br\] is \[B{{r}_{35}}=\,1{{s}^{2}},\,2{{s}^{2}},\,2{{p}^{6}},\,3{{s}^{2}},\,3{{p}^{6}},\,3{{d}^{10}},\,4{{s}^{2}},\,4{{p}^{5}}\] total electron present in p-orbitals of \[Br\] is ? \[2{{p}^{6}}+3{{p}^{6}}+4{{p}^{5}}=17.\]
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