JEE Main & Advanced Chemistry Structure of Atom Question Bank Quantum number, Electronic configuration and Shape of orbitals

  • question_answer
    The number of \[d\] electrons in \[F{{e}^{+2}}\] (atomic number of \[Fe=26\]) is not equal to that of the             [MNR 1993]

    A)                 \[p\]-electrons in \[Ne\] (At. No.= 10)

    B)                 \[s\]-electrons in \[Mg\] (At. No.= 12)

    C)                 \[d\]-electrons in \[Fe\]

    D)                 \[p\]-electrons in \[C{{l}^{-}}\] (At. No. of  \[Cl\]  = 17)

    Correct Answer: D

    Solution :

               \[_{26}Fe=[Ar]\,3{{d}^{6}},\,4{{s}^{2}}\]                    \[F{{e}^{2+}}=[Ar]\,3{{d}^{6}},\,4{{s}^{0}}\]                    Number of d-electrons = 6                    \[_{17}Cl=[Ne]\,3{{s}^{2}},\,3{{p}^{5}}\]                    \[C{{l}^{-}}=[Ne]\,3{{s}^{2}},\,3{{p}^{6}}\]                                 Number of p-electrons = 6.

You need to login to perform this action.
You will be redirected in 3 sec spinner