A) One
B) Two
C) Three
D) Four
Correct Answer: D
Solution :
\[{{C}_{6}}=1{{s}^{2}},\,2{{s}^{2}}2{{p}^{2}}\] (Ground state) \[=1{{s}^{2}}\,2{{s}^{1}}\,2P_{x}^{1}\,2p_{y}^{1}\,2p_{z}^{1}\] (Excited state) In excited state no. of unpaired electron is 4.
You need to login to perform this action.
You will be redirected in
3 sec
