• question_answer The four quantum numbers of the valence electron of potassium are                                     [DPMT 2004] A)                 4, 1, 0 and $\frac{1}{2}$              B)                 4, 0, 1 and $\frac{1}{2}$ C)                 4, 0, 0 and $+\frac{1}{2}$            D)                 4, 1, 1 and $\frac{1}{2}$

Atomic number of potassium is 19 and hence electronic configuration will be $1{{s}^{2}},\,2{{s}^{2}},\,2{{p}^{6}},\,3{{s}^{2}},\,3{{p}^{6}},\,4{{s}^{1}}$                    Hence for $4{{s}^{1}}$ electron value of Quantum number are                    Principal quantum number $n=4$                    Azimuthal quantum number $l=0$                    Magnetic quantum number $m=0$                                 Spin quantum number $s=+1/2$