JEE Main & Advanced Chemistry Structure of Atom Question Bank Quantum number, Electronic configuration and Shape of orbitals

  • question_answer
    The quantum numbers for the outermost electron of an element are given below as \[n=2,\,l=0,\,m=0,\,s=+\frac{1}{2}\]. The atoms is                                       [EAMCET 1978]

    A)                 Lithium

    B)                 Beryllium

    C)                 Hydrogen           

    D)                 Boron

    Correct Answer: A

    Solution :

     The electronic configuration must be \[1{{s}^{2}}\,2{{s}^{1}}.\] Hence, the element is lithium \[(z=3).\]


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