A) \[{{100}^{{}^\circ }},{{90}^{{}^\circ }},{{70}^{{}^\circ }}\]
B) \[{{90}^{{}^\circ }},{{60}^{{}^\circ }},{{70}^{{}^\circ }}\]
C) \[{{60}^{{}^\circ }},{{110}^{{}^\circ }},{{70}^{{}^\circ }}\]
D) \[{{100}^{{}^\circ }},{{100}^{{}^\circ }},{{80}^{{}^\circ }}\]
Correct Answer: D
Solution :
(d): By property of \[\parallel gm\] \[\angle x={{100}^{{}^\circ }}\left( opp.\text{ }\angle s \right)\] \[\angle y=\angle x={{100}^{{}^\circ }}\left( corresponding\text{ }\angle s \right)\] \[\angle z={{180}^{{}^\circ }}-\angle y={{80}^{{}^\circ }}.\]
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