question_answer

The length of each side of a rhombus is 10 cm and of its diagonals 1$ of 16cm. The length of the other diagonal is

A)  13 cm                         

B)  12 cm    

C)  \[2\sqrt{39}\] cm          

D)  6 cm

Correct Answer: B

Solution :

(b): In the given rhombus, we have: \[AB=10\]cm and \[OA=8\]cm \[\therefore \] \[O{{B}^{2}}=A{{B}^{2}}-~O{{A}^{2}}={{(10)}^{2}}-{{8}^{2}}-36\] \[\Rightarrow OB=\sqrt{36}=6cm\] \[\therefore \] \[BD=2\times OB=(2\times 6)cm=12cm\]