A) \[-(a+1),\,(a+2)\]
B) \[(a+1),\,-(a+2)\]
C) \[(a+1),(a+2)\]
D) \[-(a+1),-(a+2)\]
Correct Answer: B
Solution :
Given equation is \[{{x}^{2}}+x-(a+1)(a+2)=0\] \[\Rightarrow \]\[{{x}^{2}}+(a+2)x-(a+1)x-(a+1)\,(a+2)=0\] \[\Rightarrow \] \[x(x+(a+2))-(a+1)(x+(a+2))=0\] \[\Rightarrow \] \[(x-(a+1))\,(x+(a+2))=0\] \[\Rightarrow \] \[x=(a+1)\] or \[x=-\,(a+2)\]You need to login to perform this action.
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