A) \[9{{x}^{2}}+28x+25=0\]
B) \[9{{x}^{2}}+30x+25=0\]
C) \[9{{x}^{2}}+28x-25=0\]
D) \[16{{x}^{2}}+22x-30=0\]
Correct Answer: A
Solution :
We have. \[3{{x}^{1/2}}+5{{x}^{-1/2}}=\sqrt{2}\] \[\Rightarrow \] \[3{{x}^{1/2}}+\frac{5}{{{x}^{1/2}}}=\sqrt{2}\] \[\Rightarrow \] \[3x+5={{(2x)}^{1/2}}\] ....(1) Squaring both sides of (1), we have \[9{{x}^{2}}+25+30x=2x\] \[\Rightarrow \] \[9{{x}^{2}}+28x+25=0~\]
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