A) \[2{{x}^{2}}+6x-123=0\]
B) \[3{{x}^{2}}+33x+378=0\]
C) \[{{x}^{2}}-10x-121=0\]
D) \[{{x}^{2}}-11x-126=0\]
Correct Answer: D
Solution :
(d): At (2, 8) and (6, 72),\[y=2{{x}^{2}}=rx+t\] 8 = 2r + t and 72 = 6r + t. Solving for r and t, r = 16 and t = ? 24. The required equation is that whose roots are 18 and ? 7. Sum of its roots = 11 Product of its roots = ? 126 \[\therefore \] The required equation is \[{{x}^{2}}-11x-126=0\]
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