A) \[m+\frac{1}{m}=1,m\ne 0\]
B) \[{{m}^{2}}+\frac{1}{m}=1,m\ne 0\]
C) \[{{x}^{2}}-\frac{1}{x}=1,x\ne 0\]
D) \[{{x}^{2}}+2\sqrt{x}-1=0\]
Correct Answer: A
Solution :
(a): Upon simplifying \[m+\frac{1}{m}=1\] \[\frac{{{m}^{2}}+1}{m}=1\Rightarrow {{m}^{2}}+1=m\Rightarrow {{m}^{2}}-m+1=0\] Which is of the form \[a{{x}^{2}}+bx+c=0\]
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